[10000印刷√] z=x^2 y^2 graph 316441-Z sqrt x 2 + y 2 graph
To graph the XY plane you set Z = 0 and plot the function as you normally would, so $$z = \sqrt(x^2 y^2 1) == 0 = \sqrt(x^2 y^2 1)$$ $$\text {Therefore} x^2 y^2 = 1$$ is your XY axis graph, which is just a circle of radius 1 centered at the originLevel surfaces For a function $w=f(x,\,y,\,z) \, U \,\subseteq\, {\mathbb R}^3 \to {\mathbb R}$ the level surface of value $c$ is the surface $S$ in $U \subseteqExtended Keyboard Examples Upload Random Compute answers using Wolfram's breakthrough technology & How Do You Sketch F X Y Ln X 2 Y 2 Socratic Z sqrt x 2 + y 2 graph
